Gas Side Pressure Drop Across Tubes
The gas side pressure drop may be calculated by any number of methods available today, but the following procedures should give sufficient results for heater design.
Bare Tube Pressure Loss:
For bare tubes we can use the method presented by Winpress(Hydrocarbon Processing, 1963),
Dp = Pv /2 * Nr
Where,
Dp = Pressure drop, inH2O |
Pv = Velocity head of gas, inH2O |
Nr = Number of tube rows |
And the velocity head can be described as,
Pv = 0.0002307 * (Gn /1000)2 / rg
Where,
Gn = Mass velocity of gas, lb/hr-ft2 |
rg = Density of gas, lb/ft3 |
The Mass velocity is described as,
Gn = Wg / An
Where,
Wg = Mas gas flow, lb/hr |
An = Net free area, ft2 |
And,
An = Ad - do/12 * Le * Nt
For staggered tubes without corbels,
Ad = ((Nt +0.5) * Pt/12) * Le
For staggered tubes with corbels or inline tubes,
Ad = (Nt * Pt/12) * Le
Where,
Ad = Convection box area, ft2 |
do = Outside tube diameter, in |
Le = Tube length, ft |
Pt = Transverse pitch of tubes, in |
Nt = Number of tubes per row |
We can now use the following script to try some calculations,