Gas Side Pressure Drop Across Tubes
Page6_6 Frame
The gas side pressure drop may be calculated by any number of methods available today, but the following procedures should give sufficient results for heater design.
Bare Tube Pressure Loss:
For bare tubes we can use the method presented by Winpress(Hydrocarbon Processing, 1963),
Dp = Pv /2 * Nr
Where,
Dp = Pressure drop, inH2O |
Pv = Velocity head of gas, inH2O |
Nr = Number of tube rows |
And the velocity head can be described as,
Pv = 0.0002307 * (Gn /1000)2 / rg
Where,
Gn = Mass velocity of gas, lb/hr-ft2 |
rg = Density of gas, lb/ft3 |
The Mass velocity is described as,
Gn = Wg / An
Where,
Wg = Mas gas flow, lb/hr |
An = Net free area, ft2 |
And,
An = Ad - do/12 * Lt * Nt
For staggered tubes without corbels,
Ad = ((Nt +0.5) * Pt/12) * Le
For staggered tubes with corbels or inline tubes,
Ad = (Nt * Pt/12) * Le
Where,
Ad = Convection box area, ft2 |
do = Outside tube diameter, in |
Le = Tube length, ft |
Pt = Transverse pitch of tubes, in |
Nt = Number of tubes per row |
We can now use the following script to try some calculations,
Fin Tube Pressure Loss:
For the fin tube pressure drop, we will use the Escoa method.
Dp = ((f+a)*Gn2*Nr)/(rb*1.083E+109)
And,
For staggered layouts,
f = C2 * C4 * C6 * (df/do)0.5
For inline layouts,
f = C2 * C4 * C6 * (df/do)1.0
And,
a = ((1+B2)/(4*Nr))*rb*((1/rout)-(1/rin))
Where,
Dp = Pressure drop, inH2O |
rb = Density of bulk gas, lb/ft3 |
rout = Density of outlet gas, lb/ft3 |
rin = Density of inlet gas, lb/ft3 |
Gn = Mass gas flow, lb/hr-ft2 |
Nr = Number of tube rows |
do = Outside tube diameter, in |
df = Outside fin diameter, in |
And,
B = An / Ad
For staggered tubes without corbels,
Ad = ((Nt +0.5) * Pt/12) * Le
For staggered tubes with corbels or inlune tubes,
Ad = (Nt * Pt/12) * Le
Net Free Area, An:
An = Ad - Ac * Le * Nt
Where,
Ad = Cross sectional area of box, ft2 |
Ac = Fin tube cross sectional area/ft, ft2/ft |
Le = Effective tube length, ft |
Nt = Number tubes wide |
And, |
Ac = (do + 2 * lf * tf * nf) / 12 |
tf = fin thickness, in |
nf = number of fins, fins/in |
Reynolds correction factor, C2:
C2 = 0.07 + 8 * Re-0.45
And,
Re = Gn * do/(12*mb)
Where,
mb = Gas dynamic viscosity, lb/ft-hr |
Geometry correction, C4:
For segmented fin tubes arranged in,
a staggered pattern,
C4 = 0.11*(0.0 5*Pt/do)(-0.7*(lf/sf)^0.23)
an inline pattern,
C4 = 0.08*(0. 15*Pt/do)(-1.1*(lf/sf)^0.20)
For solid fin tubes arranged in,
a staggered pattern,
C4 = 0.11*(0.0 5*Pt/do)(-0.7*(lf/sf)^0.20)
an inline pattern,
C4 = 0.08*(0. 15*Pt/do)(-1.1*(lf/sf)^0.15)
Where,
lf = Fin height, in |
sf = Fin spacing, in |
Non-equilateral & row correction, C6:
For fin tubes arranged in,
a staggered pattern,
C6 = 1.1+(1.8-2.1*e(-0.15*Nr^2))*e(-2.0*Pl/Pt) - (0.7*e(-0.15*Nr^2))*e(-0.6*Pl/Pt)
an inline pattern,
C6 = 1.6+(0.75-1.5*e(-0.70*Nr))*e(-2.0*(Pl/Pt)^2)
Where,
Nr = Number of tube rows |
Pl = Longitudinal tube pitch, in |
Pt = Transverse tube pitch, in |
We can now use the following script to try some calculations,
Stud Tube Pressure Loss:
For the stud tube pressure loss we will use the Muhlenforth method,
The general equation for staggered or inline tubes,
Dp = Nr*0.0514*ns((Cmin-d0-0.8*ls)/((ns*(Cmin-do-1.2*ls)2)0.555))1.8*G2*((Tg+460)/1460)
Where,
Dp = Pressure drop across tubes, inH2O |
Nr = Number of tube rows |
Cmin = Min. tube space, diagonal or transverse, in |
do = Outside tube diameter, in |
ls = Length of stud, in |
G = Mass gass velocity, lb/sec-ft2 |
Tg = Average gas Temperature, °F |
Correction for inline tubes,
Dp = Dp*((do/Cmin)0.333)2
And,
G = Wg/(An*3600)
An = Le*Nt*(Pt-do-(ls*ts*rs)/12)/12
Where,
Wg = Mass flow of gas, lb/hr |
An = Net free area of tubes, ft2 |
Le = Length of tubes, ft |
Nt = Number of tubes wide |
Pt = Transverse tube pitch, in |
ls = Length of stud, in |
ts = Diameter of stud, in |
rs = Rows of studs per foot |
We can now use the following script to try some calculations,